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Java.lang.classcastexception Ljava.lang.object Cannot Be Cast To Ljava.lang.string Toarray

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share|improve this answer answered Feb 15 '12 at 12:37 amit 115k12117222 add a comment| up vote 1 down vote Use T[] toArray(T[] a) from Collection instead. What exactly does that statement do? (Hint: it has nothing to do with indexes). What is a Rotary Club Word™? My Blog on Learning Analytics Winston Gutkowski Bartender Posts: 10527 64 I like... http://bestimageweb.com/cannot-be/ljava-lang-object-cannot-be-cast-to-ljava-lang-string-toarray.php

So, to avoid ugly iteration you can simply tune your hql: You need to frame your query like this select entity from Entity as entity where ... more stack exchange communities company blog Stack Exchange Inbox Reputation and Badges sign up log in tour help Tour Start here for a quick overview of the site Help Center Detailed What does a -4 above the stave mean? List list = new ArrayList(); Then you can get a string array by using toArray(String[]), viz: String[] dump = list.toArray(new String[0]); However, I'm not sure why you think you need to hop over to this website

Ljava.lang.object Cannot Be Cast To Class

It seems like row should just be Object or String, not Object[], and that when you use it you should just use it directly, not as row[1]: Object row = combocourse.getSelectedItem(); Formula 1 rebus Why are wavelengths shorter than visible light neglected by new telescopes? Correct. If problem persist then let us know.

Is there still a way to prevent Trump from becoming president? That is what ArrayList#toArray(T[]) does. US Election results 2016: What went wrong with prediction models? Java.lang.string Cannot Be Cast To Bean Not the answer you're looking for?

The reason why it was doing so i have understood now, because i was using the .toArray() method whereas i should have used String [] dump=list.toArray(new String[]{}); Because i had wanted share|improve this answer answered Jul 25 at 11:35 Samarth S 213 add a comment| Your Answer draft saved draft discarded Sign up or log in Sign up using Google Sign Not the answer you're looking for? http://stackoverflow.com/questions/15264182/classcastexception-java-lang-object-cannot-be-cast-to-java-lang-string-andr Basically its the same program that i have been working on.

Start a coup online without the government intervening Complement of CFL is Recursive Possible repercussions from assault between coworkers outside the office How to prove that authentication system works, and that Ljava Lang Object Cannot Be Cast To Java Util List posted 3 years ago Koushik Ghosh wrote:here you don't need to return the list. Check if an item is in a nested list How to decline a postdoc interview if there is some possible future collaboration? Hibernate will use ResultSetMetadata to deduce the actual order and types of the returned scalar values.

Ljava.lang.object Cannot Be Cast To Pojo

share|improve this answer answered Oct 12 at 13:39 Глеб Ш 307 add a comment| Your Answer draft saved draft discarded Sign up or log in Sign up using Google Sign http://stackoverflow.com/questions/23651751/java-lang-string-cannot-be-cast-to-ljava-lang-object posted 5 years ago Or the method toArray(T[] a) "Any fool can write code that a computer can understand. Ljava.lang.object Cannot Be Cast To Class Out of Memory Error "+omg+"\n"); } System.out.println("The word "+wordToFind+" occurs "+count+" time's."); console.close(); output.close(); } //end method checkWordInFile public int findMatchedString(){ // Map mp=new HashMap(); for(Object value:list){ Integer freq=mp.get(value); mp.put(value, Java Lang Classcastexception Java Lang Object Cannot Be Cast To When you access the list from another method you get the modified list.

Can't u do like this? my review here Not the answer you're looking for? Passing 0 length array worked. –Maven Jul 4 at 19:35 add a comment| up vote 3 down vote You just need to get the contents of arraylist in an array, right?? more hot questions question feed lang-java about us tour help blog chat data legal privacy policy work here advertising info mobile contact us feedback Technology Life / Arts Culture / Recreation Java.lang.classcastexception: [ljava.lang.object; Cannot Be Cast To + Jpa

Post Reply Bookmark Topic Watch Topic New Topic Similar Threads String array ClassCastException ArrayList->List Coverting Array to List when i have a int[] array Question on casting getting Class cast exception Can a text in Latin be understood by an educated Italian who never had any formal teaching of that language? Now read the documentation for toArray(T[]) again, and see if you can't work out why you might write it that way. click site Why isn't the List interface acceptable?

River Crossing Puzzle Find the Emirps! Java.lang.string Cannot Be Cast To Class My Blog on Learning Analytics Winston Gutkowski Bartender Posts: 10527 64 I like... Your help would be appreciated.

Crowder Jun 19 '13 at 21:32 @assylias Good point!

See this is your code. posted 5 years ago 1 Your assumption in wrong. Exactly what error are you getting and on which line of your code? –metacubed May 14 '14 at 10:17 String can not be cast to Array of [email protected] which Java.lang.classcastexception: Java.lang.string Cannot Be Cast To share|improve this answer answered Mar 7 '13 at 6:09 kcoppock 91.7k30196221 Other solutions didn't work for me.

What crime would be illegal to uncover in medieval Europe? Winston "Leadership is nature's way of removing morons from the productive flow" - Dogbert Articles by Winston can be found here Koushik Ghosh Greenhorn Posts: 25 I like... Non-Repetitive Quine What is a satisfactory result of penetration testing assessment? navigate to this website share|improve this answer answered Feb 15 '12 at 12:39 Pablo 2,86111834 add a comment| up vote 0 down vote Use this code for listing out the values of map i.e.

Teenage daughter refusing to go to school If a wondrous item was dynamically created as slimy, can I remove the smell with prestidigitation? toArray() returns an Object[]; and in the case of ArrayList, it really IS an Object[]. Crowder 489k81781915 1 Object row[] = (Object[])it.next(); too... :) –TAsk May 14 '14 at 10:22 1 @TAsk: Well, I don't know the query infrastructure being used there, so for When you modify list in the method the global variable (list) is modified.

When you access the list from another method you get the modified list. I'm not sure if that's the problem, but it's sure as hell NOT a good idea. Build me a brick wall! public static String RepeatingWords(String s) { String []dump=new String[list.size()]; // Here list is an ArrayList of type for(int counter=0;counter