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Java Lang String Cannot Be Applied

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Best of luck. VBulletin, Copyright 2000 - 2016, Jelsoft Enterprises Ltd. It should take no parameters and just return the customer's name Was This Post Helpful? 0 Back to top MultiQuote Quote + Reply #3 William_Wilson lost in compilation Reputation: 207 they are: File: C:\Program Files\Java\New Folder\Bank.java [line: 19] Error: getName(java.lang.String) in Customer cannot be applied to () File: C:\Program Files\Java\New Folder\Driver1.java [line: 6] Error: cannot find symbol symbol : constructor Bank(int) news

do this 2. Ok, so I tried to insert book into my methods so that: firstLibrary.returnBook(Book("The Lord of the Rings")); . http://java.sun.com/docs/books/tutorial/java/nutsandbolts/arrays.html Henry Books: Java Threads, 3rd Edition, Jini in a Nutshell, and Java Gems (contributor) Paul Yule Ranch Hand Posts: 230 posted 7 years ago Brian Wimpsett wrote:hmm... I though this was the proper return type? other

Java Lang String Cannot Be Applied To Java Lang String

Now it is telling me that the symbol for Book isn't found. Posted By javanewbie82 (3 replies) 11-08-2016, 10:05 PM in New To Java Help memorizing Java code for... In the gradle.properties file both are set the correct way.

For example: public class Test { public static void main(String[] args) { int x; boolean setX = false; if (setX) { x = 10; } System.out.println(x); } } 1 error found: If a method doesn't take parameters (as your methods do), you call them like this: Java Code: getName(); // look, no parameters here getNumber(); // also no parameters here But I Problem Adding Different "Book" Objects Into A "Library" Array Errors Trying To Compare Strings All times are in JavaRanch time: GMT-6 in summer, GMT-7 in winter Contact Us | advertise | Operator Cannot Be Applied To Java.lang.object Int Win a copy of Cybersecurity Lexicon or Cyber-Physical Attack Recovery Procedures: A Step-by-Step Preparation and Response Guide in the Security forum!

Is there still a way to prevent Trump from becoming president? Operator Cannot Be Applied To Java Lang String Why is it telling me this? It looks as if you're trying to return a type of Topic, which means you'll need to override the toString() method on Topic to return the value you want. To fix it, pass a Book object.

java.lang.String cannot be cast to org.gradle.api.JavaVersion I tried: sourceCompatibility= '1.7' targetCompatibility= '1.7' but still the same problem. Cannot Be Applied To Java.lang.string Int Was This Post Helpful? 0 Back to top MultiQuote Quote + Reply #10 Brandon222 D.I.C Head Reputation: 0 Posts: 142 Joined: 16-November 08 Re: Error: cannot be applied to () Exit"); } this is in my bank class, i want it to come up in my driver class.. SitePoint Sponsor User Tag List Results 1 to 2 of 2 Thread: cannot be applied to (java.lang.String) Thread Tools Show Printable Version Subscribe to this Thread… Display Linear Mode Switch to

Operator Cannot Be Applied To Java Lang String

For example, consider the following program: public class Test { public static void main(String[] args) { myMethod(1.0, 2, "Hello!"); } public static void myMethod(double d, String s, int x) { System.out.println(s JHipster member jdubois commented Nov 18, 2014 As we don't provide that plugin by default, I don't think this is necessary. Java Lang String Cannot Be Applied To Java Lang String incompatible types This error occurs when there are type issues with your program. Object In Object Cannot Be Applied Im not quite sure what parameters your talking about.

Double quotes are for String (which implements the CharSequence interface) and single quotes are for characters. navigate to this website Excuse me for keeping this thread open, I am pretty new at Java. i try to make them match, and it gives me the same error, i even tried renaming them but nothing. Or modify your method to take a String object. Java Cannot Be Applied To Int

Was This Post Helpful? 0 Back to top MultiQuote Quote + Reply #6 Brandon222 D.I.C Head Reputation: 0 Posts: 142 Joined: 16-November 08 Re: Error: cannot be applied to () For me gradle.properties is use to set "internal props" of gradle such as deamon usage or jvm memory args for exemple . Reply With Quote 09-23-2011,11:19 AM #7 JosAH Moderator Join Date Sep 2008 Location Voorschoten, the Netherlands Posts 14,331 Blog Entries7 Rep Power 25 Re: Java Error cannot be applied to (java.lang.String), More about the author This is where your error is happening!

Why isn't this piece of code creating the array? : Maybe you can start with the Sun tutorial on arrays... Java Operator Cannot Be Applied more hot questions question feed about us tour help blog chat data legal privacy policy work here advertising info mobile contact us feedback Technology Life / Arts Culture / Recreation Science expected" error message that we encountered above.

Toshiro Hitsuguya Greenhorn Posts: 19 posted 7 years ago I have also tried to change it to firstLibrary.borrowBook(books[1]); and it is telling me a "non-static varible cannot be referenced from a

What I am trying to do is take value to combobox which is String array, and place that string into topic (where the (t) is now import java.util.Hashtable; import javax.jms.JMSException; import When using an else statement, the compiler is smart enough to see that in at least one case x will be initialized: public class Test { public static void main(String[] args) It turns out the compiler only knows that o was declared as Object but it doesn't have a way to know if that object is a string or is something else Like if you try to divide a null variable with a number.

I understand that you can't compare int with the string inside the array but I'm really stuck here and haven't got any ideas. To acknowledge this, you can use a typecast: public class Test { public static void main(String[] args) { int pi = (int)3.14159; System.out.println("The value of pi is: " + pi); } You can now find them here. http://bestimageweb.com/cannot-be/java-lang-object-cannot-be-applied-to-java-lang-string.php String is a class, a String is an object, they can't be compared in this way.

Reply With Quote 09-23-2011,11:58 AM #8 iceyferrara Member Join Date Sep 2011 Posts 10 Rep Power 0 Re: Java Error cannot be applied to (java.lang.String), phone book entry program. What is it that you are trying to do? do that etc....so far i have this: public void menu(){ System.out.println("Please enter one of the following numbers"); System.out.println("1. You can find out more information about the move and how to open a new account (if necessary) here.

I understand that u said leave out the parameters but i thought they were already left out since i left the () blank. The next line of the error message (which says "found") tells you what you (incorrectly) tried to use to call the method. I looked online and this exception was caused with an illegal use of null. Reply With Quote 09-23-2011,11:10 AM #6 iceyferrara Member Join Date Sep 2011 Posts 10 Rep Power 0 Re: Java Error cannot be applied to (java.lang.String), phone book entry program.

The main method is included below, this works fine without GUI, but I need to add it to GUI. java shack99 25 posts since Dec 2009 Community Member 2Contributors 3Replies 5Views 5 YearsDiscussion Span 5 Years Ago Last Post by jon.kiparsky 1 Featured Reply jon.kiparsky 326 5 Years Ago The JHipster member jdubois commented Nov 18, 2014 @banzera as this is issue is closed, I don't understand your comment: do you still have the problem? Results 1 to 13 of 13 Thread: Java Error cannot be applied to (java.lang.String), phone book entry program.

C++ calculator using classes In Revelation 19:16, of which kings is Jesus king? Reply With Quote 09-23-2011,12:32 PM #9 JosAH Moderator Join Date Sep 2008 Location Voorschoten, the Netherlands Posts 14,331 Blog Entries7 Rep Power 25 Re: Java Error cannot be applied to (java.lang.String), Henry Books: Java Threads, 3rd Edition, Jini in a Nutshell, and Java Gems (contributor) Toshiro Hitsuguya Greenhorn Posts: 19 posted 7 years ago Ok. If you'd like compatibility with that plugin, I can provide a PR.

Instead, the upper bound should use the < boolean operator, or an equivalent statement. You may have to register before you can post: click the register link above to proceed. When a method declaration does not contain a return type, this error will occur: public class Test { public static void main(String[] args) { int x = getValue(); System.out.println(x); } public You're allowed to do this by acknowledging to the compiler that you know that you're going to lose precision if you do the assignment.