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Java.io.filenotfoundexception Config.properties The System Cannot Find The File Specified

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David Jason Greenhorn Posts: 27 posted 4 years ago Rob Spoor wrote:That's because the current directory is the base of your package tree, not the directory local to the class file. It (usually) actually uses getResource in the background. If the folder of your project is named for e.g. Not really, it is useful for applications where you do not want to hard code file paths in your code (as long as its in CLASSPATH) So how does the class news

posted 7 years ago So how does the class loader help you if you provide the wrong file path? Can a text in Latin be understood by an educated Italian who never had any formal teaching of that language? But when I execute it using my jar through command prompt, I get an error saying java.io.FileNotFoundException: src\com\java\db\properties\connection.properties (The system cannot find the path specified) Now, when I changed my code Linked 2 Why can't my system find my properties file? 0 why do i get the error “The system cannot find the file specified?” 0 How to read my words.txt into

The System Cannot Find The File Specified Java Eclipse

Good point. In it, you'll get: The week's top questions and answers Important community announcements Questions that need answers see an example newsletter By subscribing, you agree to the privacy policy and terms In my application I have a location "src/com/java/db/properties" which contains my properties file.

Accessing files that are there in classes directory Exception while accessing .properties file. posted 7 years ago Package path is nothing but relative file path. You should switch to using resources instead; check Class.getResourceAsStream: props.load(getClass().getResourceAsStream("config.properties"));(And you should close() all your streams when done!) SCJP 1.4 - SCJP 6 - SCWCD 5 - OCEEJBD 6 - OCEJPAD The System Cannot Find The File Specified In Java With class loader , you really don't need the file path at all.

Try adding XXX/src, where XXX is the root diredctory, in your source path from command line argument "-sourcepath". Java.io.filenotfoundexception In Java Already have an account? If you get that wrong, you will still end up with an exception won't you? [How to ask questions] [Donate a pint, save a life!] [Onff-turn it on!] Balu Sadhasivam if its inside package , of course you got to give "package path" and not "file path" Package path is nothing but relative file path.

Maneesh Godbole Saloon Keeper Posts: 11279 16 I like... Java.io.filenotfoundexception Eclipse Post Reply Bookmark Topic Watch Topic New Topic programming forums Java Java JSRs Mobile Certification Databases Caching Books Engineering Languages Frameworks Products This Site Careers Other all forums Forum: Java in Netbeans is doing this thing for you that is why no issue there. Possible repercussions from assault between coworkers outside the office Wrong way on a bike lane?

Java.io.filenotfoundexception In Java

more stack exchange communities company blog Stack Exchange Inbox Reputation and Badges sign up log in tour help Tour Start here for a quick overview of the site Help Center Detailed Maneesh Godbole Saloon Keeper Posts: 11279 16 I like... The System Cannot Find The File Specified Java Eclipse J Lalit Greenhorn Posts: 15 posted 7 years ago Hi, Thanks for reply.It may be the case that i need to create the file with the same name at the given Java.io.filenotfoundexception: (the System Cannot Find The File Specified) If you want to use a FileInputStream, that should be possible too: URL url = props.getClass().getResource("config.properties"); if (url != null) { InputStream in = new FileIntputStream(url.getFile()); ... } else { //

How to prove that authentication system works, and that customer uses the wrong password? navigate to this website posted 7 years ago Class loaders are helpful only for resources packaged inside jar files. The are not going to help you out if you provide the wrong file path. InputStream in = this.getClass().getResourceAsStream("src/com/java/db/properties/connection.properties"); Properties props = new Properties(); props.load(in); in.close(); And by doing this I get null pointer exception at props.load(in). Java Io Filenotfoundexception The System Cannot Find The Path Specified

getProperties() method has started java.io.FileNotFoundException: message.properties (The system cannot find the file specified) at java.io.FileInputStream.open(Native Method) at java.io.FileInputStream.(FileInputStream.java:106) FUBAR!! Yeah , that's obvious. Related 581What is the difference between JSF, Servlet and JSP?1217How to avoid Java code in JSP files?0Can't connect Tomcat 6 and oracle 10g XE for jsp database connectivity0I am unable to More about the author Drawing a torso with a head (using \draw) Wrong way on a bike lane?

If you move the JAR file, or the folder with the classes and resources, or simply execute the program from a different directory, the resource will still be found. Java Io Filenotfoundexception No Such File Or Directory Place the property file under any directory which is in CLASSPATH and load it. What do you get when you do System.out.println(System.getProperty("user.dir")); Is your properties file at that location? [How to ask questions] [Donate a pint, save a life!] [Onff-turn it on!] Balu Sadhasivam

That being said, you need to determine if the file is to be an embedded-resource (or just "resource" - terms which sometimes I'll use interchangeably).

more stack exchange communities company blog Stack Exchange Inbox Reputation and Badges sign up log in tour help Tour Start here for a quick overview of the site Help Center Detailed Why does the following line give a FileNotFoundException? For example, if you changed your project structure to ProjectRoot\src\resources\word.txt, you could use this: InputStream is = Hangman1.class.getResourceAsStream("/resources/word.txt"); BufferedReader reader = new BufferedReader(new InputStreamReader(is)); getResourceAsStream returns an InputStream, but obtains an Java.io.filenotfoundexception (access Is Denied) Why it May not Work For one, the working directory could always change.

Message: "); e.getMessage(); System.out.print("Stacktrace: "); e.printStackTrace(); } } public static void main(String[] args) { System.out.println("AM STARTING...."); new PropertiesTest().getProperties(); } } Runtime output: init: deps-module-jar: deps-ear-jar: deps-jar: compile-single: run-main: AM STARTING.... Post Reply Bookmark Topic Watch Topic New Topic programming forums Java Java JSRs Mobile Certification Databases Caching Books Engineering Languages Frameworks Products This Site Careers Other all forums Forum: I/O and In an IDE like Netbeans, put the file in the project folder, not the source folder –hotforfeature Nov 9 '13 at 3:29 add a comment| 6 Answers 6 active oldest votes http://bestimageweb.com/the-system/java-io-filenotfoundexception-jdbc-properties-the-system-cannot-find-the-file-specified.php You can access classpath resource in a number of ways.

I meant , loading resources with Class Loader's inputstream has advantages rather than depending on FileInputStream. What happens under the hood ? This solved it for me. getResource() will return an URL For Maven users, where the directory structure is like src/main/resources, the contents of the resources folder is put at the root of the classpath.

If you get that wrong, you will still end up with an exception won't you? Safety - Improve braking power in wet conditions more hot questions question feed lang-java about us tour help blog chat data legal privacy policy work here advertising info mobile contact us parameter for FileInputStream must be absolute path of config file share|improve this answer answered Sep 10 '13 at 7:45 Chin Tsao 563 add a comment| Your Answer draft saved draft Is your .properties file in the folder containing the .class files?

posted 7 years ago J Lalit wrote:It may be the case that i need to create the file with the same name at the given location prior to saving the file??If posted 4 years ago Mike Simmons wrote: If you want to use a FileInputStream, that should be possible too: URL url = props.getClass().getResource("config.properties"); if (url != null) { InputStream in = I changed the path according to it in my code and it worked like a charm. I admit the user here is talking about running it in Eclipse, but I think ultimately the application will end up being packaged. [My Blog] [JavaRanch Journal] David Jason Greenhorn

Since you're on windows when you have notepad open and do 'save as' select 'all files'(not a windows but it something to that affect). Safety - Improve braking power in wet conditions Drawing a torso with a head (using \draw) Why did Borden do that to his wife in The Prestige? The working directory, can be described as this: When you run from the command line C:\EclipseWorkspace\ProjectRoot\bin > java com.mypackage.Hangman1 the working directory is C:\EclipseWorkspace\ProjectRoot\bin. If it doesn't exist, you get: "This file does not exist".

I was trying to split your command and I get errors. posted 4 years ago Jaikiran Pai wrote:That I believe will fail if that config.properties ultimately ends up being within a jar distribution of that application. That's why you should use getResourceAsStream when you need an InputStream. Place the file there and you'll be good to go.